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	added hw3 answers
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							| @ -0,0 +1,117 @@ | ||||
| Part B: Choose one of Questions 10 or 11 | ||||
| 
 | ||||
| 5. We now examine the differences between LDA and QDA. | ||||
| 
 | ||||
|     (a) If the Bayes decision boundary is linear, do we expect LDA | ||||
|     or QDA to perform better on the training set? On the test set? | ||||
| 
 | ||||
|         The QDA has more flexibility, so it will match the training | ||||
|         set more closely than the LDA. The LDA will perform better | ||||
|         on the test set because the real relationship is linear, so | ||||
|         the QDA would have additional bias. | ||||
| 
 | ||||
| 
 | ||||
|     (b) If the Bayes decision boundary is non-linear, do we expect | ||||
|     LDA or QDA to perform better on the training set? On the test | ||||
|     set? | ||||
| 
 | ||||
|         QDA will still perform better on the training set, but now | ||||
|         should also perform better than LDA on the test set, since | ||||
|         QDA will account for the additional degree of freedom in the | ||||
|         real relationship. | ||||
| 
 | ||||
| 
 | ||||
|     (c) In general, as the sample size n increases, do we expect the | ||||
|     test prediction accuracy of QDA relative to LDA to improve, | ||||
|     decline, or be unchanged? Why? | ||||
| 
 | ||||
|         Definitely increase. The LDA has an advantage when the | ||||
|         training set is small because it is less sensitive to the | ||||
|         fluctuations of those few data. As the size of the training | ||||
|         set grows, the QDA is able to optimize its coefficients | ||||
|         well, and assuming the real relationship is not linear, the | ||||
|         QDA should eventually out-perform the LDA. | ||||
| 
 | ||||
| 
 | ||||
|     (d) True or False: Even if the Bayes decision boundary for a | ||||
|     given problem is linear, we will probably achieve a superior | ||||
|     test error rate using QDA rather than LDA because QDA is | ||||
|     flexible enough to model a linear decision boundary. Justify | ||||
|     your answer. | ||||
| 
 | ||||
|         False. The QDA will likely be biased because it will fit to | ||||
|         training data that don't completely represent the | ||||
|         relationship that will be observed in test data. | ||||
| 
 | ||||
| 
 | ||||
| 8. Suppose that we take a data set, divide it into equally-sized | ||||
|    training and test sets, and then try out two different | ||||
|    classification procedures. First we use logistic regression and | ||||
|    get an error rate of 20 % on the training data and 30 % on the | ||||
|    test data. Next we use 1-nearest neighbors (i.e. K = 1) and get | ||||
|    an average error rate (averaged over both test and training data | ||||
|    sets) of 18 %. Based on these results, which method should we | ||||
|    prefer to use for classification of new observations? Why? | ||||
| 
 | ||||
|         Definitely 1-nearest neighbor. The logistic regression | ||||
|         performed more poorly on the training data, to which it has | ||||
|         been optimized as much as possible, and yet the nearest | ||||
|         neighbor model performs better over the entire dataset. | ||||
|         Considering the logistic regression performed even worse on | ||||
|         the test data, the average error rate of the logistic | ||||
|         regression over the training and test data is 25%. This | ||||
|         suggests that the relationship may not even be linear, and | ||||
|         the nearest-neighbor is a very solid method for modeling | ||||
|         non-linear classifications, so if the real relationship is | ||||
|         not linear, it easily explains why the nearest-neighbor | ||||
|         method would do so much better. Everything here seems to | ||||
|         point at using the nearest-neighbor. | ||||
| 
 | ||||
| 
 | ||||
| 9. This problem has to do with odds. | ||||
| 
 | ||||
|     (a) On average, what fraction of people with an odds of 0.37 of | ||||
|     defaulting on their credit card payment will in fact default? | ||||
| 
 | ||||
|     (b) Suppose that an individual has a 16 % chance of defaulting | ||||
|     on her credit card payment. What are the odds that she will de- | ||||
|     fault? | ||||
| 
 | ||||
| 
 | ||||
| 
 | ||||
| 11. In this problem, you will develop a model to predict whether a | ||||
|     given car gets high or low gas mileage based on the Auto data | ||||
|     set. | ||||
| 
 | ||||
|     (a) Create a binary variable, mpg01 , that contains a 1 if mpg | ||||
|     contains a value above its median, and a 0 if mpg contains a | ||||
|     value below its median. You can compute the median using the | ||||
|     median() function. Note you may find it helpful to use the | ||||
|     data.frame() function to create a single data set containing | ||||
|     both mpg01 and the other Auto variables. | ||||
| 
 | ||||
|     (b) Explore the data graphically in order to investigate the | ||||
|     associ- ation between mpg01 and the other features. Which of the | ||||
|     other features seem most likely to be useful in predicting mpg01 | ||||
|     ? Scat- terplots and boxplots may be useful tools to answer this | ||||
|     ques- tion. Describe your findings. | ||||
| 
 | ||||
|     (c) Split the data into a training set and a test set. | ||||
| 
 | ||||
|     (d) Perform LDA on the training data in order to predict mpg01 | ||||
|     using the variables that seemed most associated with mpg01 in | ||||
|     (b). What is the test error of the model obtained? | ||||
| 
 | ||||
|     (e) Perform QDA on the training data in order to predict mpg01 | ||||
|     using the variables that seemed most associated with mpg01 in | ||||
|     (b). What is the test error of the model obtained? | ||||
| 
 | ||||
|     (f) Perform logistic regression on the training data in order to | ||||
|     pre- dict mpg01 using the variables that seemed most associated | ||||
|     with mpg01 in (b). What is the test error of the model obtained? | ||||
| 
 | ||||
|     (g) Perform KNN on the training data, with several values of K, | ||||
|     in order to predict mpg01 . Use only the variables that seemed | ||||
|     most associated with mpg01 in (b). What test errors do you | ||||
|     obtain? Which value of K seems to perform the best on this data | ||||
|     set? | ||||
							
								
								
									
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