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1) Estimate the temperature of the warm dust emission.
Read the wavelength at the peak of the blackbody region.
λₚₑₐₖ = 10¹³ Hz.
Using Wien Law,
λₚₑₐₖ = 2.90 × 10⁻³ m K / T.
T = 2.90 × 10⁻³ m K / 10¹³ Hz.
T = 96.7 K.
2) What is the turnover frequency of the brems emission?
This is just gleaned from the SED.
1.5 GHz = 1.5 × 10⁹ Hz.
3) Assume that the brems comes from ionized hydrogen at 10 4 K and
a density of 10 4 cm -3 . What is the thickness of NGC 7027 in cm?
In parsecs?
κʹₛ = 0.0178 Z² g ν⁻² T^(-3/2) nₑ nₗ.
g = 10.6 + 1.9*log(T) - 1.26*log(Z*ν)
= 6.63.
κʹₛ = 0.0178 × 1 × (3.32) × (1.5 × 10⁹ Hz)⁻² × (10⁴ K)^(-3/2) × (10⁴ cm⁻³)².
κʹₛ = 5.25 × 10⁻¹⁸ cm⁻¹.
For turnover frequency,
1 = τ = κʹₛ l.
l = τ / κʹₛ = κʹₛ⁻¹.
l = 1.90 × 10¹⁷ cm
= 0.0617 parsecs.
After fixing the typo from the Allen text, this seems to be a much more reasonable result. The actual radius (from wikipedia) is approximately .068 parsec for this object, so this is very close to that answer.